ГДЗ Математика 6 клас Істер — Вправа 1039

$\left(-2\frac{3}{8} + \left(-2\frac{1}{4}\right)\right) + \left(-7\frac{5}{6} + \left(-2\frac{5}{12}\right)\right) = -14\frac{7}{8}$

1) $-2\frac{3}{8} + \left(-2\frac{1}{4}\right) = -\left(2\frac{3}{8} + 2\frac{2}{8}\right) = -4\frac{5}{8};$

2) $-7\frac{5}{6} + \left(-2\frac{5}{12}\right) = -\left(7\frac{10}{12} + 2\frac{5}{12}\right) = -9\frac{15}{12} = -10\frac{3}{12} = -10\frac{1}{4};$

3) $-4\frac{5}{8} + \left(-10\frac{1}{4}\right) = -\left(4\frac{5}{8} + 10\frac{2}{8}\right) = -14\frac{7}{8}.$