ГДЗ Математика 6 клас Істер — Вправа 300

1) $7\frac{3}{4} - 2\frac{5}{6} - 3\frac{3}{8} = 7\frac{18}{24} - 2\frac{20}{24} - 3\frac{9}{24} =$

$= 6\frac{42}{24} - 2\frac{20}{24} - 3\frac{9}{24} = 4\frac{22}{24} - 3\frac{9}{24} = 1\frac{13}{24};$

2) $10\frac{8}{15} - 4\frac{1}{12} + 5\frac{7}{20} = 10\frac{32}{60} - 4\frac{5}{60} + 5\frac{21}{60} =$

$= 6\frac{27}{60} + 5\frac{21}{60} = 11\frac{48}{60} = 11\frac{4}{5};$

3) $12\frac{5}{8} + 7\frac{2}{3} - 11\frac{3}{16} = 12\frac{30}{48} + 7\frac{32}{48} - 11\frac{9}{48} =$

$= 19\frac{62}{48} - 11\frac{9}{48} = 8\frac{53}{48} = 9\frac{5}{48};$

4) $8\frac{23}{25} - 3\frac{7}{10} - 2\frac{1}{5} = 8\frac{46}{50} - 3\frac{35}{50} - 2\frac{10}{50} =$

$= 5\frac{11}{50} - 2\frac{10}{50} = 3\frac{1}{50};$

5) $19 - (4\frac{1}{6} + 11\frac{3}{4}) = 19 - (4\frac{2}{12} + 11\frac{9}{12}) =$

$= 19 - 15\frac{11}{12} = 18\frac{12}{12} - 15\frac{11}{12} = 3\frac{1}{12};$

6) $2\frac{5}{6} + (7 - 2\frac{7}{10}) = 2\frac{5}{6} + (6\frac{10}{10} - 2\frac{7}{10}) =$

$= 2\frac{5}{6} + 4\frac{3}{10} = 2\frac{25}{30} + 4\frac{9}{30} = 6\frac{34}{30} = 7\frac{4}{30} = 7\frac{2}{15}.$