ГДЗ Математика 6 клас Істер — Вправа 303

1) $9\frac{13}{50} - 0,86 + 3\frac{7}{8} = 9\frac{26}{100} - \frac{86}{100} + 3\frac{7}{8} = 8\frac{126}{100} - \frac{86}{100} + 3\frac{7}{8} =$

$= 8\frac{40}{100} + 3\frac{7}{8} = 8\frac{2}{5} + 3\frac{7}{8} = 8\frac{16}{40} + 3\frac{35}{40} = 11\frac{51}{40} = 12\frac{11}{40};$

2) $3,25 + \frac{5}{8} - 1\frac{3}{16} = 3\frac{25}{100} + \frac{5}{8} - 1\frac{3}{16} = 3\frac{1}{4} + \frac{5}{8} - 1\frac{3}{16} =$

$= 3\frac{4}{16} + \frac{10}{16} - 1\frac{3}{16} = 3\frac{14}{16} - 1\frac{3}{16} = 2\frac{11}{16}.$