ГДЗ Математика 6 клас Істер — Вправа 372

1) $4\frac{1}{2} \cdot 2\frac{4}{9} + 1\frac{1}{2} \cdot 2\frac{4}{9} = 2\frac{4}{9} \cdot (4\frac{1}{2} + 1\frac{1}{2}) = \frac{22}{9} \cdot 6 = \frac{44}{3} = 14\frac{2}{3};$

2) $3\frac{2}{3} \cdot 7\frac{1}{5} - 1\frac{1}{6} \cdot 7\frac{1}{5} = 7\frac{1}{5} \cdot (3\frac{4}{6} - 1\frac{1}{6}) = \frac{36}{5} \cdot 2\frac{1}{2} = \frac{36}{5} \cdot \frac{5}{2} = 18;$

3) $4\frac{5}{8} \cdot 2 = (4 + \frac{5}{8}) \cdot 2 = 4 \cdot 2 + \frac{5}{8} \cdot 2 = 8 + \frac{5}{4} = 8 + 1\frac{1}{4} = 9\frac{1}{4};$

4) $(1\frac{5}{6} - 1\frac{1}{3}) \cdot 3 = 1\frac{5}{6} \cdot 3 - 1\frac{1}{3} \cdot 3 = \frac{11}{6} \cdot 3 - \frac{4}{3} \cdot 3 = \frac{11}{2} - 4 =$

$= 5,5 - 4 = 1,5 = 1\frac{1}{2}.$