ГДЗ Математика 6 клас Істер — Вправа 373

1) $3\frac{2}{9} \cdot 1\frac{3}{5} + 1\frac{3}{5} \cdot 6\frac{7}{9} = 1\frac{3}{5} \cdot (3\frac{2}{9} + 6\frac{7}{9}) = \frac{8}{5} \cdot 10 = 16;$

2) $4\frac{7}{9} \cdot 1\frac{1}{11} - 3\frac{5}{9} \cdot 1\frac{1}{11} = 1\frac{1}{11} \cdot (4\frac{7}{9} - 3\frac{5}{9}) =$

$= \frac{12}{11} \cdot 1\frac{2}{9} = \frac{12}{11} \cdot \frac{11}{9} = \frac{4}{3} = 1\frac{1}{3};$

3) $3\frac{2}{3} \cdot 3 = (3 + \frac{2}{3}) \cdot 3 = 3 \cdot 3 + \frac{2}{3} \cdot 3 = 9 + 2 = 11;$

4) $(2\frac{1}{4} - \frac{5}{8}) \cdot 4 = 2\frac{1}{4} \cdot 4 - \frac{5}{8} \cdot 4 = \frac{9}{4} \cdot 4 - \frac{5}{2} = 9 - 2\frac{1}{2} = 6\frac{1}{2}.$