ГДЗ Математика 6 клас Істер — Вправа 542

1) $2,375 : \left(\frac{3}{4}\right)^2 \cdot (4\frac{1}{2} - 2\frac{1}{19}) = 10\frac{1}{3};$

1) $4\frac{1}{2} - 2\frac{1}{19} = 4\frac{19}{38} - 2\frac{2}{38} = 2\frac{17}{38} = \frac{93}{38};$

2) $2,375 = 2\frac{3}{8} = \frac{19}{8};$

3) $\left(\frac{3}{4}\right)^2 = \frac{9}{16};$

4) $\frac{19}{8} : \frac{9}{16} \cdot \frac{93}{38} = \frac{19}{8} \cdot \frac{16}{9} \cdot \frac{93}{38} = \frac{2}{9} \cdot 93 = \frac{31}{3} = 10\frac{1}{3}.$

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2) $(\frac{2}{3})^3 \cdot 1\frac{11}{16} + (4\frac{9}{25} - 3\frac{13}{20}) = 1,21;$

1) $(\frac{2}{3})^3 = \frac{8}{27};$

2) $\frac{8}{27} \cdot 1\frac{11}{16} = \frac{8}{27} \cdot \frac{27}{16} = \frac{1}{2} = 0,5;$

3) $4,36 - 3,65 = 0,71;$

4) $0,5 + 0,71 = 1,21.$

Відповідь: 1) $10\frac{1}{3};$ 2) $1,21.$